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Two similar capillary tubes of sufficient length long are placed in water. One is placed vertically and the other is placed at 60⁰ with the vertical. The length of the liquid raised into tubes is in the ratio

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1 : 3

$\sqrt{2} : \sqrt{3}$

3 : 2

1 : 2

answer is D.

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Detailed Solution

Given,

$θ_{1} = 60^{ο}, θ_{2} = 0^{ο}$

From the question.

The vertical height to which the fluid raises is same in both the cases.

$vertical height h = l_{2} {cosθ}_{2} = l_{1} {cosθ}_{1}$

$\Rightarrow \frac{l_{1}}{l_{2}} = \frac{{cosθ}_{2}}{{cosθ}_{1}} = \frac{\cos 60^{°}}{\cos 0^{°}} = \frac{1}{2}$

Hence the correct answer is 1:2.

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