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Q.

Two skaters have weight in the ratio 4 : 5 and are 9 m apart, on a smooth frictionless surface. They pull on a rope stretched between them. The ratio of the distance covered by them when they meet each other will be 

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a

5:4

b

4:5

c

25:16

d

16:25

answer is A.

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Detailed Solution

Acceleration of the skaters will be in the ratio

a1:a2=F4:F5  or  5:4

Here F is the tension in string.

Now according to the problem, s=0+12at2, we get

s1s2=a1a2=54

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