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Two slabs A & B having lengths l₁ and l₂, respectively, and same cross - section have thermal conductivities K₁ and K₂ respectively. They are placed in contact and a constant temperature difference is maintained across the combination. The ratio of the quantities of heat flowing through A and B in a given time is:

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\large \frac {K_1}{l_1}:\frac {K_2}{l_2}

\large \frac {K_1}{l_2}:\frac {K_2}{l_1}

1 : 1

answer is D.

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Detailed Solution

Rate of flow is same in series (constant temperature difference is maintained)

$∴ {(\frac{Q}{t})}_{A} : {(\frac{Q}{t})}_{B} = 1 : 1$

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