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Q.

Two slits in Young's double slit experiment are placed 1mm from each other. Interference pattern is observed on a screen placed 1m from the plane of slits. What is the angular fringe width for a light of wavelength 400 nm ?

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a

400 rad

b

4×10−6rad

c

400×10−6rad

d

40×10−6rad

answer is B.

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Detailed Solution

d=1mm =10−3m

D=1m 

λ=400 nm=400×10−9m

Angular width  θ=λd=400×10−910−3rad

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