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Two slits separated by a distance of 1 mm, are illuminated with red light of wavelength 6.5 X 10^-7 m. The interference fringes are observed on a screen placed 1 m from the slits. The distance between the third dark fringe and the fifth bright fringe is equal to

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0.65 mm

4.88 mm

1.63 mm

3.25 mm

answer is B.

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Detailed Solution

$Δ y = \frac{5 λ D}{d} - \frac{5 λ D}{2 d} = \frac{5 λ D}{2 d}$

$= \frac{5 \times 6.5 \times 10^{- 7} \times 1}{2 \times 10^{- 3}} m = 1.63 mm$

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