Two small balls of masses 3m and 2m and each having charges Q are connected by a string passing over a fixed pulley. Calculate the acceleration of the balls (in m/sec2) if the whole assembly is located in a uniform electric field E = mg/2Q acting vertically downwards. Neglect any interaction between the balls. Take g=10 m/s2.

Force on m1 and m2 due to electric field = Q1E and Q2E downward Let acceleration of both masses is 'a' as shown in figure: By Both equations: a=(m2−m1)g+(Q2−Q1)Em1+m2And by putting m1=2m, m2=3m, and Q1=Q2 we get a=2m/sec2

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Two small balls of masses 3m and 2m and each having charges Q are connected by a string passing over a fixed pulley. Calculate the acceleration of the balls (in m/sec²) if the whole assembly is located in a uniform electric field E = mg/2Q acting vertically downwards. Neglect any interaction between the balls. Take $g = 10 m / s^{2} .$

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Force on $m_{1}$ and $m_{2}$ due to electric field = $Q_{1} E$ and $Q_{2} E$ downward Let acceleration of both masses is 'a' as shown in figure:

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By Both equations: $a = \frac{(m_{2} - m_{1}) g + (Q_{2} - Q_{1}) E}{m_{1} + m_{2}}$
And by putting $m_{1} = 2 m, m_{2} = 3 m,$ and $Q_{1} = Q_{2}$ we get $a = 2 m / \sec^{2}$