Q.

Two small equal point charges of magnitude q are suspended from a common point on the ceiling by insulating mass less strings of equal lengths. They come to equilibrium with each string making angle θ from the vertical. If the mass of each charge is m, then the electrostatic potential at the centre of line joining them will be 14π0=k

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a

k mg tan θ

b

2k mg tan θ

c

3k mg tan θ

d

4k mg tan θ

answer is C.

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Detailed Solution

Question Image

tanθ=Fmg

F=q24πε0x2

tanθ=q24πε0mgx2

x=q24πε0mgtanθ

x=kq2mgtanθ...(i)

V=kqx2+kqx2

Using (i)  V=4kmgtanθ

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Two small equal point charges of magnitude q are suspended from a common point on the ceiling by insulating mass less strings of equal lengths. They come to equilibrium with each string making angle θ from the vertical. If the mass of each charge is m, then the electrostatic potential at the centre of line joining them will be 14π∈0=k