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Two small identical discs A and B each of mass $m = 2 k g$ placed on a frictionless horizontal floor are connected by light inextensible string of length $l = 2 m$ . Now the midpoint C of cord is pulled perpendicular to the line joining centres of the discs by a constant force $F = 8 N$ . In the subsequent motion, when they are about to collide:

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Tension in the string is 8N

Velocity of approach of discs A and B is 4m/s

Acceleration of midpoint C of the cord is rightward

Magnitude of acceleration of midpoint C of the cord is $2 m / s^{2}$

answer is B, D.

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Detailed Solution

$v_{a p p} = \sqrt{\frac{2 F l}{m}} a_{c} = ω^{2} \frac{l}{2} - \frac{F}{2 m}$

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