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Q.

Two soap bubbles are in air. Pressure inside two soap bubbles are 1.01 and 1.02 atmospheres. Ratio between their volumes is

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a

8 : 1

b

1 : 80

c

102 : 101

d

(102)3:(101)3

answer is C.

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Detailed Solution

Excess pressure

ΔP=Pin−Pout =1.01atm−1atm=0.01atm and similarly ΔP2=0.02atm

∴V1V2=(ΔP2ΔP1)3=(0.020.01)3=(21)3=81

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