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Q.

Two soap bubbles combine under isothermal conditions to form a single soap bubble. If in this process, the change in volume is ‘V’ and change in area is ‘S’, then

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a

3PV+4TS=0

b

PV+TS=0

c

3PV+TS=0

d

4PV+3TS= 0

answer is C.

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Detailed Solution

$(P + \frac{4 T}{C}) \frac{4}{3} π C^{3} = (P + \frac{4 T}{a}) \frac{4}{3} π a^{3} + (P + \frac{4 T}{b}) \frac{4}{3} π b^{3}$
$\frac{4}{3} π p (c^{3} - a^{3} - b^{3}) = \frac{4}{3} T (4 π a^{2} + 4 π b^{2} - 4 π c^{2})$
$P V = \frac{4}{3} T (- S)$
$3 P V = - 4 T S$
$3 P V + 4 T S = 0$

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