Two soap bubbles have radii in the ratio 2 : 1. What is the ratio of excess of pressure inside them ?

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1 :4

1 :2

4: 1

2:1

answer is A.

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Detailed Solution

$Excess of pressure = \frac{4 T}{r} \propto \frac{1}{r} p_{1} \propto 1 / 2 r and ρ_{2} \propto 1 / r p_{1} / p_{2} = \frac{1}{2} or p_{1} : p_{2} = 1 : 2$

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