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Two solid bodies of equal masses are heated at a uniform rate under identical conditions. The change in temperature (taken on Y axis) in the two cases is shown graphically.

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The ratio of their specific heats in solid state is 1:3

The ratio of their specific heats in solid state is 1:2

The ratio of their latent heats is 2:1

The ratio of their latent heats is 4:1

answer is A, C.

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Detailed Solution

$θ = m L = P t L_{1} : L_{2} = P (4) : P (2) = 2 : 1 S_{1} : S_{2} = \frac{P t_{1}}{Δ T_{1}} : \frac{P t_{2}}{(Δ T_{2})} = \frac{P (2)}{60} : \frac{P (4)}{40} = \frac{1}{3} : 1 = 1 : 3$

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