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Two solid rubber balls A and B having masses 200 & 400 gm respectively are moving in opposite direction with velocity of A equal to 0.3 m/sec. After collision the two balls come to rest then the velocity of B is

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None of the above

1.5 m/sec

0.15 m/sec

$- 0.15 m / \sec$

answer is A.

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Detailed Solution

$m_{1} = 0.2 k g, m_{2} = 0.4 k g, v_{1} = 0.3 m / s, v_{2} = ?$

Applying law of conservation of momentum

$\Rightarrow m_{1} v_{1} = m_{2} v_{2} v_{2} = \frac{0.2 \times 0.3}{0.4} = 0.15 m / s$

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