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Two solution of a substance (nonelectrolyte) are mixed in the following manner 480 mL of 1.5 M of first solution with 520 mL of 1.2 M of second solution. The molarity of final solution is

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1.20 M

1.50 M

1.344 M

2.70 M

answer is C.

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Detailed Solution

solution(1): $M_{1} = 1.5 M, V_{1} = 480 ml$

Solution(2): $M_{2} = 1.2 M, V_{2} = 520 ml$

$resultant Molarity = \frac{M_{1} V_{1} + M_{2} V_{2}}{V_{1} + V_{2}} = \frac{1.5 \times 480 + 1.2 \times 520}{480 + 520} = \frac{1344}{1000} = 1.344 M$

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