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Q.

 Two sound waves of relative intensities 400 : 1 show interference. The ratio of intensity at the maxima to minima is close to

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a

401 /399

b

21 /19

c

11/9

d

401 /399

answer is A.

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Detailed Solution

Ia2

At maxima a=a1+a2
At maxima a′′=a1a2
Given that relative intensities are 400 : 1 r'.e., amplitudes arc in the ratio 20 : 1
Ratio of intensity at maxima =(20+1)2(201)2

=(21)2(19)2119

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