Two spheres A and B of radius 4cm and 6cm are given charges of 80μc and 40μc respectively. If they are connected by a fine wire, the amount of charge flowing from one to the other is

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16 $μ$ C from A to B

32 $μ$ C from B to A

32 $μ$ C from A to B

20 $μ$ C from A to B

answer is D.

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Detailed Solution

Total charge A = 80+20=120 $μ$ C. By using the formula ${Q_{1}}^{'} = Q [\frac{r_{1}}{r_{1} + r_{2}}]$
New charge on sphere A is $Q_{A}^{'} = Q [\frac{r_{A}}{r_{A} + r_{B}}] = 120 [\frac{4}{4 + 6}] = 48 μC .$
Initially it was i.e., charge flows from A to B.

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