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Q.

Two spheres have a volume ratio of 64 : 27. If the sum of their radii is 7 cm, then the difference in their surface areas is ____ c m 2 .  


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Detailed Solution

Two spheres have a volume ratio of 64 : 27. If the sum of their radii is 7 cm, then the difference in their surface areas is 88 c m 2 .   It is given that the volume of two spheres is in the ratio of 64 : 27 and the sum of their radii is 7 cm.
We know that the volume of a sphere is 4 3 π r 3   and its surface area is 4π r 2 ,   where r is the sphere’s sphere.
Let’s assume that the radius of one sphere is r cm.   Therefore from the question, we have,
The radius of another sphere is 7r cm.  
The ratio of their volumes is 64 : 27.
4 3 π r 3 4 3 π 7r 3 = 64 27 r 7r 3 = 4 3 3   r 7r = 4 3 3r=284r  
7r=28 r=4cm   Therefore, the radius of one sphere is 4 cm.   The radius of another sphere is 74 cm = 3 cm.  
Therefore the difference in their surface areas can be calculated as,
D=4π 4 2 4π 3 2 D=4π 169 D=4× 22 7 ×7 D=88  cm 2  
Therefore, the difference in their surface areas is 88 cm 2 .  
 
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