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Two spheres having radii of 5 cm and 10 cm bear identical charges of 6.6 nC. Find the potentials of spheres after they have been connected by a conductor. Assume that the spheres are at large distance from each other

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1200 V

600 V

396 V

792 V

answer is C.

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Detailed Solution

r < R $(q_{1} = q_{2})$ so charge flows from smaller to bigger until their potential are equal

after they are joined

$\frac{q_{1}}{5} = \frac{q_{2}}{10}$

$\frac{q_{1}}{q_{2}} = \frac{1}{2}$

$q_{1} = \frac{2 q}{3} \times 1; q_{2} = \frac{2 q}{3} \times 2$

$q_{1} = \frac{2 \times 6.6}{3} n c = 4.4 n c$

$V = \frac{1}{4 π ε_{o}} \frac{4.4}{5 \times 10^{- 2}} = \frac{9 \times 10^{9} \times 4.4 \times 10^{- 9}}{5 \times 10^{- 2}} = 792 V$

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