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Two spheres of the same material have radii 1m and 4m and temperature 4000K and 2000K respectively. The energy radiated per second by the first sphere is :

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greater than that of the second

less than that of the second

equal in both cases

the information is incomplete to draw any conclusion

answer is C.

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Detailed Solution

$P = {σAT}^{4} = σ 4 {πr}^{2} T^{4} \Rightarrow \frac{P_{1}}{P_{2}} = {(\frac{r_{1}}{r_{2}})}^{2} \times {(\frac{T_{1}}{T_{2}})}^{4}$

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