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Two spherical vessels of equal volume, are connected by a narrow tube. The apparatus contains an ideal gas at one atmosphere and 300 K. Now if one vessel is immersed in a bath of constant temperature 600 K and the other in a bath of constant temperature 300 K. Then the common pressure will be

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1 atm

$\frac{4}{5} atm$

$\frac{4}{3} atm$

$\frac{3}{4} atm$

answer is C.

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Detailed Solution

Apply conservation of moles

$\begin{array}{l} \frac{(1 atm) (2 V)}{(R) (300)} = \frac{PV}{R (600)} + \frac{PV}{R (300)} \\ \Rightarrow 2 = \frac{3 P}{2} \Rightarrow P = \frac{4}{3} atm \end{array}$

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