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Q.

Two springs A and B have force constants k_A and K_B, respectively, with k_A > K_B. Both springs are stretched by the same force, then the work done is :

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a

greater in case of spring A

b

none of the above

c

same in both cases

d

smaller in case of spring A

answer is C.

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Detailed Solution

Work done by spring force $= \frac{1}{2} {kx}^{2} = \frac{(kx)^{2}}{2 k} = \frac{F^{2}}{2 k}$

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