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Q.

Two springs are in a series combination and are attached to a block of mass $' m'$ which is in equilibrium . The spring constants and the extension in the springs are as shown in the figure. Then the force exerted by the spring on the block is:

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a

$\frac{k_{1} k_{2}}{k_{1} + k_{2}} (x_{1} + x_{2})$

b

$k_{1} x_{1} + k_{2} x_{2}$

c

$k_{1} x_{1}$

d

$k_{2} x_{2}$

answer is A, D, C.

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Detailed Solution

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Spring force $F = k_{1} x_{1} = k_{2} x_{2}$

Where $x_{1} & x_{2}$ are the elongation of springs

Question Image

Also $F = k_{e} (x_{1} + x_{2})$

$= \frac{k_{1} k_{2}}{(k_{1} + k_{2})} (x_{1} + x_{2})$

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Two springs are in a series combination and are attached to a block of mass 'm' which is in equilibrium . The spring constants and the extension in the springs are as shown in the figure. Then the force exerted by the spring on the block is: