Two springs have their force constants as K1 and K2 (K1 > K2). The work done, when both are stretched by the same amount of length, will be :

W1=12K1x2 W2=12K2x2K1>K2 ⇒ W1>W2

Two springs have their force constants as K1 and K2 (K1 > K2). The work done, when both are stretched by the same amount of length, will be :

W1=12K1x2 W2=12K2x2K1>K2 ⇒ W1>W2

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Two springs have their force constants as K₁ and K₂(K₁ > K₂). The work done, when both are stretched by the same amount of length, will be :

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equal

greater for K₁

greater for K₂

given data is incomplete

answer is B.

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$W_{1} = \frac{1}{2} K_{1} x^{2} W_{2} = \frac{1}{2} K_{2} x^{2}$

$K_{1} > K_{2} \Rightarrow W_{1} > W_{2}$

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Two springs have their force constants as K1 and K2 (K1 > K2). The work done, when both are stretched by the same amount of length, will be :

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Two springs have their force constants as K₁ and K₂(K₁ > K₂). The work done, when both are stretched by the same amount of length, will be :