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Two springs, of force constants $K_{1} & K_{2}$ , are connected to a mass m as shown. The frequency of oscillation of the mass is f. if both $K_{1} & K_{2}$ are made four times their original values, the frequency of oscillation becomes

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$\frac{f}{2}$

$\frac{f}{4}$

answer is D.

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Detailed Solution

$f = \frac{1}{2 π} \sqrt{\frac{K_{1} + K_{2}}{m}}, f^{1} = \frac{1}{2 π} 2 \sqrt{\frac{K_{1} + K_{2}}{m}} = 2 f$

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