Two springs P and Q having stiffness constants k₁, and k₂(< k₁), respectively are stretched equally. Then

Since ${\mathrm{k}}_1>{\mathrm{k}}_2$.

$W=\frac{1}{2}k{x}^2$

Therefore, P will develop greater restoring force than Q. So the applied force on P will be more than the applied force on Q. Extension is same in both the cases. So, more work will be done on P.