Two stable isotopes of lithium $_{3}^{6} Li {and}_{3}^{7} Li$ have respective abundances of 7.5% and 92.5%. These isotopes have masses 6.01512u and 7.01600u,respectively. Then the atomic mass of lithium is

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5.941 u

6.491 u

6.941 u

6.149 u

answer is C.

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Detailed Solution

$\begin{array}{l} M_{av} = \frac{7 .5 \times 6 .01512 + 92 .5 \times 7 .01600}{100} \\ = \frac{45 .1134 + 648 .98}{100} = \frac{694 .0934}{100} \\ M_{av} = 6 .941 u \end{array}$

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