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Two steel spheres approach each other head on with the same speed and collide elastically. After the collision one of the sphere's of radius 3cm comes to rest. the radius of the other sphere is (cm)

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$\frac{3}{{(3)}^{1 / 3}}$

${(3)}^{1 / 2} 3$

answer is A.

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Detailed Solution

If $v_{1} = 0 = \frac{m_{1} - m_{2}}{m_{1} + m_{2}} u_{1} - \frac{2 m_{2}}{m_{1} + m_{2}} u_{1}$

$m_{1} - m_{2} = 2 m 2$

$m_{1} = 3 m_{2}$

$m_{2} = \frac{m_{1}}{3} \Rightarrow r_{2} = \frac{r_{1}}{3^{1 / 3}} \Rightarrow \frac{3}{3^{1 / 3}}$

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