Q.

Two stones are thrown up simultaneously from the edge of a cliff with initial speed v and 2v. The relative position of the second stone with respect to first varies with time till both the stones strike the ground as

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a

first linearly then parabolically

b

linearly

c

first parabolically then linearly (assume that the first stone comes to rest after striking the ground)

d

parabolically

answer is B.

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Detailed Solution

Initially when both are in air, the relative acceleration between them is zero. Therefore, relative position versus-time graph is a straight line. Once the first ball reaches the ground, its acceleration becomes zero. Therefore, the relative acceleration is now g and the graph is parabolic.

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Two stones are thrown up simultaneously from the edge of a cliff with initial speed v and 2v. The relative position of the second stone with respect to first varies with time till both the stones strike the ground as