Two stones are thrown up simultaneously from the edge of a cliff 240 m high with initial speed of 10 m/s and 40 m/s respectively. Which of the following graphs best represents the time variation of relative position of the second stone with respect to the first? (Assume stones do not rebound after hitting the ground and neglect air resistance, take g = 10 $m/s^2$)

(The figures are schematic and not drawn to scale.)

For the second stone time required to reach the ground is given by y = ut -$\frac{1}{2}{\mathrm{gt}}^2$

-240 = 40t-$\frac{1}{2}{\mathrm{gt}}^2$

$\therefore 5{\mathrm{t}}^2-40\mathrm{t}-240 = 0$

(t-12)(t+8) = 0

$\therefore \mathrm{t} = 12 \mathrm{s}$

For the first stone:  $-240 = 10\mathrm{t}-\frac{1}{2}\times 10\times {\mathrm{t}}^2$

$\therefore -240 = 10\mathrm{t}-5{\mathrm{t}}^2$

$5{\mathrm{t}}^2-10\mathrm{t}-240 = 0$

(t-8)(t+6) = 0

T = 8 s

During first 8 seconds both the stones are in air:

$\therefore {\mathrm{y}}_2-{\mathrm{y}}_1 = ({\mathrm{u}}_2-{\mathrm{u}}_1)\mathrm{t} = 30\mathrm{t}$

So, the graph of $({\mathrm{y}}_2-{\mathrm{y}}_1) \mathrm{against} \mathrm{t} \mathrm{is} \mathrm{a} \mathrm{straight} \mathrm{line}.$

After 8 seconds,

${\mathrm{y}}_2 = {\mathrm{u}}_2\mathrm{t} - \frac{1}{2}{\mathrm{gt}}^2-240$

Stone two has acceleration with respect to stone one. 

Will be the nearest description.