Two stones are thrown vertically upwards simultaneously from the same point on the ground with initial speed $u_{1} = 30 m / s$ and $u_{2} = 50 m / s$ . For the time interval in which both reach the ground, which of the curve represent correct variation of $(x_{2} - x_{1}) =$ the relative position of second stone with respect to first with time (t)?
$(v_{2} - v_{1}) =$ the relative velocity of second stone with respect to first with time (t).
Assume that stones do not rebound after hitting.

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answer is A, D.

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Detailed Solution

When both the balls in the air, their relative acceleration is zero. So, their relative velocity will be constant. When the first stone reaches ground and does not rebound, relative acceleration of second stone w.r.t. the first stone is g . So, their relative velocity will increase linearly and their separation parabollically.

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