Two stones of masses m and 2m are whirled in horizontal circles, the heavier one in radius $\frac{r}{2}$ and the lighter one in radius r. The tangential speed of lighter stone is n times that of the value of heavier stone when they experience same centripetal forces. The value of n is

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answer is D.

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Detailed Solution

According to question, two stones experience same centripetal force

$i.e. F_{C_{1}} = F_{C_{2}}$

$or, \frac{{mv}_{1}^{2}}{r} = \frac{2 {mv}_{2}^{2}}{(\frac{r}{2})} or, V_{1}^{2} = 4 V_{2}^{2}$

$So, V_{1} = 2 V_{2} i.e., n = 2$

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