Two straight wires are one above the other separated by a distance of 5cm. The same current flows through the wires in opposite direction such that the upper wire which is of length 10 cm is supported without falling. If the mass of the wire is 5gm, then the current in the wire is

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35 A

3.5 A

350 A

0.35 A

answer is C.

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Detailed Solution

$\begin{array}{l} Mg = \frac{μ_{0} i_{1} i_{2} l}{2 πr}; \frac{μ_{0} i^{2} l}{2 πr} = Mg \\ 5 \times 10^{- 3} \times 10 = \frac{4 π \times 10^{- 7} \times i^{2} \times 10 \times 10^{- 2}}{2 π \times 5 \times 10^{- 2}} \end{array}$
i = 350A

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