Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was $56\%$ of the sum of their marks. The marks obtained by them are:

Let one student obtain x marks

$\because$ Marks obtained by other students $=(x+9)$ marks

According to the question 

$\begin{array}{l}(x+9)=(x+x+9)\times \frac{56}{100}\\ x+9=2x+9\times \frac{14}{25}\end{array}$

$\begin{array}{l}25x+225=28x+126\\ 3x=99\\ x=33\end{array}$

So, the marks obtained by them are - 33, 42.