Two tall buildings are 200m apart. A ball must be thrown horizontally with a speed $(2 N + 2) m / s$ from the window 540m above the ground in one building, so that it will enter a window 50m above the ground in the other. Then the value of N is $(T a k e g = 9.8 m s^{- 2})$

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answer is 9.

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Detailed Solution

Taking point A as origin and the axes as shown in for path A to B, we have R=200m.
H=540 – 50=490 m
For horizontal projection, we have $R = u \sqrt{\frac{2 H}{g}}$

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$\Rightarrow u = R \sqrt{\frac{g}{2 H}} = 200 \times \sqrt{\frac{9.8}{2 \times 490}} = 20 m / s, N = 9$

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