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Two tall buildings are 30 m apart. The speed with which a ball must be thrown horizontally from a window 150 m above the ground in one building so that it enters a window 27.5 m from the ground in the other building is: (Take $g = 9.8 m \sec^{- 2})$

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$2 {ms}^{- 1}$

$6 {ms}^{- 1}$

$4 {ms}^{- 1}$

$8 {ms}^{- 1}$

answer is B.

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Detailed Solution

Horizontal projection from height

$\begin{array}{l} R = \sqrt{\frac{2 H}{g}} \cdot u \\ 30 = \sqrt{\frac{2 \times 122.5}{9.8}} u \\ 30 = 5 \times u \\ u = 6 {ms}^{- 1} \end{array}$

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