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Q.

Two thin dielectric slabs of dielectric constants $K_{1}$ and $K_{2}$ $(K_{1} < K_{2})$ are inserted between plates of a parallel plate capacitor, as shown in the figure. The variation of electric field 'E' between the plates with distance 'd' as measured from plate P is correctly shown by:

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a

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b

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c

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d

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answer is C.

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Detailed Solution

$Electric field, E \propto \frac{1}{K} As K_{1} < K_{2} so E_{1} > E_{2}$

Hence graph

Question Image

correctly depicts the variation of electric field E with distance d.

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Two thin dielectric slabs of dielectric constants K1 and K2 (K1<K2) are inserted between plates of a parallel plate capacitor, as shown in the figure. The variation of electric field 'E' between the plates with distance 'd' as measured from plate P is correctly shown by: