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Two thin lenses when in contact produces a combination of power +10 D. When they are 0.25 m apart, the power reduces to +6 D . The focal length of the lenses are

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1 m and 0.5 m

0.125 m and 0.5 m

0.125 m and 0.4 m

0.125 m and 1 m

answer is A.

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Detailed Solution

$P = P_{1} + P_{2} = 10 . . . . (1)$

$P = P_{1} + P_{2} - d P_{1} P_{2} = 6 . . . . . . . (2)$

d = 0.25 m

solving , we get,

f₁ = 0.125 m and f₂ = 0.5 m

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