Two thin metal strips one of brass and the other of iron are fastened together parallel to each other, a distance 1mm apart to form a bimetallic strip. If the strips are of equal length at 0∘C, the radius of the arc formed by the bimetallic strip when heated to 60∘C is (coefficient of linear-expansion of brass is 19×10-6/0C and of iron =12×10−6/0C )

R=dα1−α2=1×10−37×10−6×60=2.380m

Two thin metal strips one of brass and the other of iron are fastened together parallel to each other, a distance 1mm apart to form a bimetallic strip. If the strips are of equal length at 0∘C, the radius of the arc formed by the bimetallic strip when heated to 60∘C is (coefficient of linear-expansion of brass is 19×10-6/0C and of iron =12×10−6/0C )

R=dα1−α2=1×10−37×10−6×60=2.380m

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Two thin metal strips one of brass and the other of iron are fastened together parallel to each other, a distance $1 mm$ apart to form a bimetallic strip. If the strips are of equal length at $0^{\circ} C$ , the radius of the arc formed by the bimetallic strip when heated to $60^{\circ} C$ is (coefficient of linear-expansion of brass is $19 \times 10^{- 6} /^{0} C$ and of iron $= 12 \times 10^{- 6} /^{0} C$ )

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0.57m

3.57m

2.38m

5.57m

answer is B.

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Detailed Solution

$R = \frac{d}{α_{1} - α_{2}} = \frac{1 \times 10^{- 3}}{7 \times 10^{- 6} \times 60} = 2 .380 m$

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