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Q.

Two thin prisms are combined to form an achromatic combination for 1^st prism $A = 4^{0}, μ_{R} = 1.35, μ_{v} = 1.42 for 2^{nd}$ prism $μ_{R} = 1.7, μ_{v} = 1.9$ Find angle of 2^nd prism

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a

$2^{0}$

b

${1.8}^{0}$

c

${1.6}^{0}$

d

${1.4}^{0}$

answer is D.

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Detailed Solution

$A_{1} (μ_{V} - μ_{R}) = A_{2} (μ_{V}^{'} - μ_{R}^{'})$

$\Rightarrow 4 (1.42 - 1.35) = A_{2} (1.9 - 1.7)$

$\Rightarrow A_{2} = 1.4$

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