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Q.

Two thin wood screens A and B are separated by 200m. A bullet travelling horizontally at a speed of $600 {ms}^{- 1}$ hits the screen A, penetrates through it and finally emerges out from B making holes in A and B. If the resistance of air and wood are negligible, the difference of heights of the holes in A and B is

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a

\frac{49}{90} m

b

5 m

c

Zero

d

\frac{7}{\sqrt{90}} m

answer is B.

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Detailed Solution

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$R = u \sqrt{\frac{2 (h_{1} - h_{2})}{g}}$

$Δ h = h_{1} - h_{2}$

$200 = 600 \sqrt{\frac{2 Δ h}{9.8}}$

$1 = 3 \sqrt{\frac{2 Δ h}{9.8}}$

$1 = 9 (\frac{2 Δ h}{9.8})$

$\frac{4.9}{9} = Δ h$

$Δ h = \frac{49}{90} m$

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Two thin wood screens A and B are separated by 200m. A bullet travelling horizontally at a speed of 600 ms−1 hits the screen A, penetrates through it and finally emerges out from B making holes in A and B. If the resistance of air and wood are negligible, the difference of heights of the holes in A and B is