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Two trains A and B of length 400 m each are moving on two parallel tracks with a uniform speed of 72 km h^–1 in the same direction, with A ahead of B. The driver of B decides to overtake A and accelerates by 1 m s^–2 . If after 50 s, the guard of B just brushes past the driver of A, what was the original distance between them? (In METRES)

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answer is 1250.

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Detailed Solution

If d is the distance between them

$d = \frac{1}{2} a t^{2}$

$d = \frac{1}{2} \times 1 \times 2500 = 1250$

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