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Two trains are moving towards each other at speed of 144 km/hr and 54 km/ hr relative to the ground. The second sounds a whistle of frequency 710 Hz, the frequency of this whistle as heard by a passenger in the first after the trains crossed each other is $x \times 10^{2} Hz$ , the value of x is $(v = 340 m / s)$

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answer is 6.

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Detailed Solution

$n^{'} = (\frac{v - v_{0}}{v + v_{s}}) n \Rightarrow n^{'} = [\frac{340 - 15}{340 + 40}] 710 \Rightarrow n^{'} = 607.05 Hz$

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