Two trains P and Q of length 300m and 500m are moving on two parallel tracks each with a uniform speed of 72 km/h in the same direction, with Q ahead of P. The driver of train P decide to overtake train Q and accelerates by 2.0m /s², if after 40s the guard of P just brushes past the driver of Q, then the original distance between the trains is

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800 m

450 m

1300 m

650 m

answer is C.

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Detailed Solution

$\begin{array}{l} S_{Rel} = U_{Rel} t + \frac{1}{2} a_{Rel} t^{2} \\ (x + 800) = 0 + \frac{1}{2} (2 - 0) 40^{2} \\ x + 800 = 1600 \Rightarrow x = 800 m \end{array}$
x → original distance between trains

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