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Two transparent elevator cars A and B are moving in front of each other. Car A is moving up and retreading at $a_{1},$ While car is B moving down and retreading at $a_{2} .$ Person in car A drops a coin inside the car. What is the acceleration observed by person in car B?

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$g + a_{2}$ downward

$g - a_{1} - a_{2}$ downward

$g - a_{1} + a_{2}$ downward

All of these

answer is A.

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Detailed Solution

When coin is dropped inside $' A'$ it becomes the case of free fall,
$∴ a_{c / g} = g a_{B / g} = - a_{2} {\bar{a}}_{c / B} = {\bar{a}}_{c / g} + {\bar{a}}_{g / B} ∴ a_{c / B} = g + a_{2} (i n d o w n w a r d)$

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