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Q.

Two uniform strings A and B made of steel are made to vibrate under the same tension. If the first overtone of A is equal to the second overtone of B and if the radius of A is twice that of B, the ratio of the lengths of the strings is:

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a

1 : 2

b

1 : 3

c

1 : 4

d

1 : 6

answer is B.

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Detailed Solution

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First overtone of string A = Second overtone of string B.

 Second harmonic of A = Third harmonic of B

n2=n32n1A=3n1B

n1=12Tπr2ρ

212ArATπρ=312BrBTπρ

AB=23rBrAAB=23×rB2rB=13

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Two uniform strings A and B made of steel are made to vibrate under the same tension. If the first overtone of A is equal to the second overtone of B and if the radius of A is twice that of B, the ratio of the lengths of the strings is: