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Two unknown resistance X and Y are connected to left and right gaps of a meter bridge and the balancing point is obtained at 80 cm from left. When a $10 Ω$ resistance is connected in parallel to 'X' , the balance point is 50 cm from left. The values of X and Y respectively are

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$40 Ω, 9 Ω$

$30 Ω, 7.5 Ω$

$20 Ω, 6 Ω$

$10 Ω, 3 Ω$

answer is B.

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Detailed Solution

from meter bridge formula

$\frac{x}{80} = \frac{y}{20}$

$a g a i n \frac{\frac{10 x}{10 + x}}{50} = \frac{y}{50}$

$Solving we get x = 30, y = 7.5$

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