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Two unknown resistances x and y are connected in the left and right gaps of a metre bridge and the balancing point is obtained at 50 cm from the left. When a 20 Ω resistance is connected in series to x, the balance point is 60 cm. Calculate x and y. (in ohms)

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40,10

40,20

20,10

40,40

answer is D.

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Detailed Solution

$\begin{array}{l} \frac{x}{y} = \frac{50}{50} ∴ x = y; \frac{x + 20}{y} = \frac{60}{40}; 2 x + 40 = 3 x \\ \frac{x + 20}{x} = \frac{3}{2}; x = 40 Ω; y = 40 Ω \end{array}$

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