Two vector A→=3i^+8j^−2k^ and B→=6i^+16j^+xk^ are such that the component of B→ perpendicular toA→ is zero. Then the value of x will be :

A→=3i^+8j^−2k^ B→=6i^+16j^+xk^ |i^j^k^38−2616x| =(8x+32)−(3x+12)+0=0 5x+20=0 5x=−20 x=−4

Two vector A→=3i^+8j^−2k^ and B→=6i^+16j^+xk^ are such that the component of B→ perpendicular toA→ is zero. Then the value of x will be :

A→=3i^+8j^−2k^ B→=6i^+16j^+xk^ |i^j^k^38−2616x| =(8x+32)−(3x+12)+0=0 5x+20=0 5x=−20 x=−4

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Two vector $\vec{A} = 3 \hat{i} + 8 \hat{j} - 2 \hat{k} and \vec{B} = 6 \hat{i} + 16 \hat{j} + x \hat{k}$ are such that the component of $\vec{B}$ perpendicular to $\vec{A}$ is zero. Then the value of x will be :

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\vec{A} = 3 \hat{i} + 8 \hat{j} - 2 \hat{k}

$\vec{B} = 6 \hat{i} + 16 \hat{j} + x \hat{k}$

$| \begin{matrix} \hat{i} & \hat{j} & \hat{k} \\ 3 & 8 & - 2 \\ 6 & 16 & x \end{matrix} |$

$= (8 x + 32) - (3 x + 12) + 0 = 0$

$5 x + 20 = 0$

$5 x = - 20$

$x = - 4$

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Two vector A→=3i^+8j^−2k^ and B→=6i^+16j^+xk^ are such that the component of B→ perpendicular toA→ is zero. Then the value of x will be :

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Two vector $\vec{A} = 3 \hat{i} + 8 \hat{j} - 2 \hat{k} and \vec{B} = 6 \hat{i} + 16 \hat{j} + x \hat{k}$ are such that the component of $\vec{B}$ perpendicular to $\vec{A}$ is zero. Then the value of x will be :