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Two vector $\vec{A} and \vec{B}$ have same magnitude a. If resultant of these two vector also magnitude a. Then the angle between two vectors $\vec{A} and \vec{B}$ will be

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0º

60º

120º

90º

answer is D.

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Detailed Solution

$R = \sqrt{A^{2} + B^{2} + 2 ABcos θ} a = \sqrt{a^{2} + a^{2} + 2 a^{2} \cos θ} \cos θ = \frac{- 1}{2} \Rightarrow θ = 120^{\circ}$

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