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Q.

Two vectors are given by a¯=2i^+j^3k^andb¯=5i^+3j^2k^.  If 3a¯+2b¯c¯=0 then third vector c¯ is

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a

4i^9j^+13k^

b

4i^+9j^13k^

c

2i^3j^13k^

d

4i^9j^13k^

answer is B.

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Detailed Solution

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Given is 3a¯+2b¯c¯=0

   3(2i^+j^3k^)+2(5i^+3j^2k^)=c¯.

c¯=4i^+9j^13k^

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